The equation below will be used to determine the vapor pressure of isopropanol in this experiment:

$lnP=-(\frac{H_{\text{v}\text{a}\text{p}}}{RT})+C$

$21\mathrm{.}1C,27\mathrm{.}2C,33\mathrm{.}9C$ and $13\mathrm{.}1$with the measured vapor pressure $56\mathrm{.}4mmHg,80\mathrm{.}0mmHg,95\mathrm{.}1mmHg,$ and $48\mathrm{.}1mmHg,$ respectively. After processing the data, you obtained the following graph with linear fitting equation and $R^2$ value. What is the $H_{\text{v}\text{a}\text{p}}$ in $k\frac{J}{m}ol?$ Please keep $3$ SIGs. Only enter numerical part of your answer.