The equation for the instantaneous voltage across a discharging capacitor is given by v = Voe where Vo is the initial voltage and is the time constant of the circuit. The tasks are to: a) Draw a graph of voltage against time for Vo 10s. = 12V and T = 2s, between t = 0s and t = b) Calculate the gradient at t = 2s and t = 4s. t dv c) Differentiate v = 12e 2 and calculate the value of at t = 2s and t = 4s. dt d) Compare your answers for part b and part c. e) Calculate the second derivative of the instantaneous voltage (2). t