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The equation f(x) is given as x+4x+1=0. Considering the initial approx then the value of X1 is given as a) 1.67 b) 1.87 c) 1.85

The equation f(x) is given as x+4x+1=0. Considering the initial approx then the value of X1 is given as a) 1.67 b) 1.87 c) 1.85 d) 1.86

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