The figure shown above is a binary images I in which white pixels have values of one and black pixels have values of zero. First compute derivatives of the image intensities in the x and y directions following the numerical way to obtain Ix and Iy: Ix(i,1)= (I(i+1,j)-I(1-1,3)/2 and Iyi,j) = (I(i, j+1)-I(i,j-1)}/2. For the computation of Ix[i,j) on pixels in the first column Ixci,j) = [(i+1,1) - I(ij) or of Iyci,j) on pixels in the first row Iyci,j) = Ici, j+1) - I(1,1). For the computation of Ix[i,j) on pixels in the last column Ix[i,j) = Ici,j) - I(1-1,j) or of Iyci,j) on pixels in the last row IyCi,j) = Ii,j) - Ici,j-1). Calculate the response of the Harris corner detector at each pixel based on Ix and ly, assuming (i) a value of k=0.05 in the calculation, (ii) that products of derivatives are summed over an equally weighted 3 by 3 pixel window around each pixel, (iii) that the image is padded with zeros when computing at pixels on the edge. ANSWER: R= (to 2 decimal places)