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The first step of the mechanism of the reaction of propanoic acid (3 Carbons) with methanol (CH3OH) in the presence of sulfuric acid (H2SO4) involves

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The first step of the mechanism of the reaction of propanoic acid (3 Carbons) with methanol (CH3OH) in the presence of sulfuric acid (H2SO4) involves the formation of which intermediate? H3CC. .. CH3 H3C - 4 , Clear my holice

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