The following $10$ instances are marked as positive $($Pi$)$ and negative $($Ni$).$ A single Perceptron is

used to divide the input space into two classes based on the instances. The resulting decision

boundary$/$hyperplane is shown in Figure $2.$

P$1=(4,1)$

P$2=(2,1)$

P$3=(2,2)$

P$4=(5,5)$

P$5=(3,2)$

N$1=(3,4)$

N$2=(1,1)$

N$3=(3,6)$

N$4=(3,1)$

N$5=(2,3)$

The cut$-$off points of the hyperplane are at $(0,1\mathrm{.}25)$ and $(-1,0).$

$4$

COS$4852/$A$2$

x

y

$(-1,0)$

$(0,1\mathrm{.}25)$

$-5-4-3-2-1123456$

$-3$

$-2$

$-1$

$1$

$2$

$3$

$4$

$5$

$6$

P$1$

P$2$

P$3$

P$4$

P$5$

N$1$

N$2$

N$3$

N$4$

N$5$