The following C code counts the number of "1" in j and returns the answer in k. The operation j & 0 times 01 tests the value of the LSb of j. k = 0;//init bit count for (i = 0: i! = 8: i++) {//do for 8 bits if (j & 0 times 01) { k++;//LSb = 1, increment count } j = j > > 1: //look at next bit } Write an assembly program and single step the program to verify the result. You need to assign an initial number for the file register j