Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

The following code takes in an integer (number of strings), and then allows the input of that many lines of parenthesis strings, and goes on

The following code takes in an integer (number of strings), and then allows the input of that many lines of parenthesis strings, and goes on to determine if they are balanced. I need it adjusted so that instead of taking the integer, and then each string line, one at a time, it takes in the integer number, then each string line BEFORE doing any calculating, BUT still calculating the balance for each line seperately.

For example, the code should alternatively be able to take in at text file with nothing but the following written:

3

()()

{}{}{{{{]][}{}

()()(){}}}{}{{{

The output should still be to print the integer, then string 1 and YES, then string 2 and NO, then string 3 and NO.

Let me know if you have any questions

#include #include

struct strNode { char data; struct strNode *next; };

void push(struct strNode** start, int _new); int pop(struct strNode** start);

int isMatchingPair(char character1, char character2) { if (character1 == '(' && character2 == ')') return 1; else if (character1 == '{' && character2 == '}') return 1; else if (character1 == '[' && character2 == ']') return 1; else return 0; }

int areParenthesisBalanced(char str[]) { int i = 0;

struct strNode *stack = NULL;

while (str[i]) {

if (str[i] == '{' || str[i] == '(' || str[i] == '[') push(&stack, str[i]);

if (str[i] == '}' || str[i] == ')' || str[i] == ']') {

if (stack == NULL) return 0;

else if ( !isMatchingPair(pop(&stack), str[i]) ) return 0; } i++; }

if (stack == NULL) return 1; else return 0; }

int main() { char str[100]; int i,j; scanf("%d",&j);

getchar();

for(i=0;i

{ fgets(str, sizeof str, stdin); if(str[0]==' ') {printf("Balanced "); exit(0);} if (areParenthesisBalanced(str)) printf("Yes "); else printf("No ");

} return 0; }

void push(struct strNode** start, int _new) {

struct strNode* new_node = (struct strNode*) malloc(sizeof(struct strNode));

if (new_node == NULL) { printf("Stack overflow "); getchar(); exit(0); }

new_node->data = _new;

new_node->next = (*start);

(*start) = new_node; }

int pop(struct strNode** start) { char res; struct strNode *top;

if (*start == NULL) { printf("Stack overflow "); getchar(); exit(0); } else { top = *start; res = top->data; *start = top->next; free(top); return res; } }

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Students also viewed these Databases questions