The following data are from a completely randomized design. Treatment Treatment Treatment A B C 32 47 34 30 46 37 30 47 36 26 49 37 32 51 41 Sample mean 30 48 37 Sample variance 6.00 4.00 6.50 a. At the o = 0.05 level of significance, can we reject the null hypothesis that the means of the three treatments are equal? Compute the values below (to 1 decimal, if necessary). Sum of Squares, Treatment 570 Sum of Squares, Error 66 Mean Squares, Treatment 636 Mean Squares, Error 5.5 Calculate the value of the test statistic (to 2 decimals).b. Calculate the value of Fisher's LSD (to 2 decimals). Use Fisher's LSD procedure to test whether there is a significant difference between the means for treatments A and B, treatments A and C, and treatments B and C. Use a = 0.05. Difference Absolute Value Conclusion TA - CB 15 Significant difference 6 Significant difference CB - C 9 Significant difference c. Use Fisher's LSD procedure to develop a 95%% confidence interval estimate of the difference between the means of treatments A and B (to 2 decimals). Enter negative values as negative numbers. (-19.47 X -10.52