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the following differential equation, find the integrating factor, the general solution, and the particular solution satisfying the given initial condition. y' +y=42x6ex: y(0) =
the following differential equation, find the integrating factor, the general solution, and the particular solution satisfying the given initial condition. y' +y=42x6ex: y(0) = 15 The integrating factor is I(x)= ex The general solution is y = 6x7 C + ex 6x7 15 The particular solution is y =
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