The following information is given for mercury at $1$atm :

$T_b=356\mathrm{.}60C$

$T_m=-39\mathrm{.}00C$

Specific heat solid $=0\mathrm{.}1410\frac{J}{g*C}$

$H_{\text{v}\text{a}\text{p}}(356\mathrm{.}60C)=295\mathrm{.}6\frac{J}{g}$

$H_{\text{f}\text{u}\text{s}}(-39\mathrm{.}00C)=11\mathrm{.}60\frac{J}{g}$

Specific heat liquid $=0\mathrm{.}1390\frac{J}{g*C}$

A $22\mathrm{.}20g$ sample of solid mercurv is initially at $-52\mathrm{.}00C.$ If the sample is heated at constant pressure $)=(1$atm, $19\mathrm{.}00C.$

$kJ$ of heat are needed to raise the temperature of the sample to