The following information is given for mercury at $1$ atm:

boiling point $=357C$

$H_{\text{v}\text{a}\text{p}}(357C)=59\mathrm{.}3$

melting point $=-39Ck\frac{J}{m}ol$

$H_{\text{f}\text{u}\text{s}}(-39C)=2\mathrm{.}33$

$k\frac{J}{m}ol$

specific heat solid $=0\mathrm{.}141$

$\frac{J}{g}C$

specific heat liquid $=0\mathrm{.}139$

$\frac{J}{g}C$

What is $H$ in kJ for the process of freezing a $20\mathrm{.}4g$ sample of liquid mercury at its normal melting point of $-39C.$

kJ