The following integral has a couple of errors. State what the errors are and give the correct answer. You do not need to show your own solution. Work it out yourself but then just tell us what the correct answer is. 3cos(3x) dx (sin(3x))4 U = sin(3x) du = 3cos(3x )dx U = sin(3x) du = 3cos(3x )dx if X = - 18 then u = sin 6 if x = - 6 then u = sin = 1 3cos(3x) dx = du = 1 (u-4) du 18 (sin(3x))4 w / - 303 w /- 1 1 27 26 w - 3 3 3 3 33