The following is a set of hypotheses, some information from one or more samples, and a standard error from a randomization distribution. Test Ho : p = 0.27 vs Ha : p Pc where po and p. represent the proportion of fruit flies alive at the end of the given time frame of those eating organic food and those eating conventional food, respectively. Use a 5 % significance level. Effect of Organic Soybeans After 5 Days After 5 days, the proportion of fruit flies eating organic soybeans still alive is 0.92 , while the proportion still alive eating conventional soybeans is 0.85 . The standard error for the difference in proportions is 0.022 . What is the value of the test statistic? Round your answer to two decimal places. 2 i What is the p-value? Round your answer to three decimal places. p-value= i What is the conclusion? Is there evidence of a difference?MORE BENEFITS OF EATiNG ORGANlC Using specic data, we nd a signicant difference in the proportion of fruit ies surviving after 13 days between those eating organic potatoes and those eating conventional (not organic] potatoes. This exercise asks you to conduct a hypothesis test using additional data. In this case, we are testing H0 :po = p8 PIMP.) 3* P: wh ere p0 and p6. represent the proportion of fruit ies alive at the end of the given time frame of those eating organic food and those eating conventional food, respectively. Use a 5 % signicance level. Effect of Organic Potatoes After 1 1 Days After 11 days. the proportion of fruit ies eating organic potatoes still alive is 0.68 . while the proportion still alive eating conventional potatoes is 0. 65 . The standard error for the difference in proportions is 0.031 . What is the value of the test statistic? Round your answer to two decimal places. What is the p-yalue'.' Round your answer to three decimal places. What is the conclusion? I:| Is there evidence of a difference? |:| Part 1 (a) A 78% confidence interval for a proportion. Round your answer to two decimal places. +2* = + i eTextbook and Media Hint Save for Later Attempts: unlimited Submit Answer Part 2 (b) An 82% confidence interval for a slope. Round your answer to two decimal places. +2* = + i eTextbook and Media Hint Save for Later Attempts: unlimited Submit Answer Part 3 (c) A 92 % confidence interval for a standard deviation. Round your answer to two decimal places. +2* i eTextbook and Media HintFind the indicated confidence interval. Assume the standard error comes from a bootstrap distribution that is approximately normally distributed. A90 % confidence interval for a mean y if the sample has n = 20 withx = 22.6 and s = 5.9, and the standard error is SE = 1.32. Round your answers to three decimal places. The 90 % confidence interval is i to 1Part 1 (a) Find a 95 % confidence interval for the difference in the proportion saying they used online dating, between men and women. The standard error of the estimate is 0.016. Round your answers to three decimal places. The 95 % confidence interval is i to i eTextbook and Media Hint Save for Later Attempts: unlimited Submit Answer Part 2 (b) Is it plausible that there is no difference between men and women in how likely they are to use online dating? Use the confidence interval from part (a) to answer. O Yes O No eTextbook and Media Hint Save for Later Attempts: unlimited Submit AnswerMore informtion From the Online Dating Survey A surveyIr conducted in Julyr 2015 asked a random sample of American adults whether they had ever used online dating [either an online dating site or a dating app on their cell phone}. 55- to 64-year-olds The survey included 41 1 adults between the ages of 55 and 64, and 50 of them said that they had used online dating. If we use this sample to estimate the proportion of all American adults ages 55 to 64 to use online dating, the standard error is 0.016. Find a 95% condence interval for the proportion of all US adults ages 55 to 64 to use online dating. Round your answers to three decimal places