The following system has one solution:

x=2,y=-2

, and

z=3

.\

4x-2y+5z=27,

Equation 1\

x+y=0

Equation 2\

-x-3y+2z=10,

Equation 3 parameter

t_(. )

)\

(x,y,z)=(,)

\ parameter

t

.)\

(x,y,z)=(,)

\ parameter

t

.)\

(x,y,z)=()

\ (d) How many solutions does each of these systems have?\ Equations 1 anct2:\ zero\ one\ infinitely many\ Equations 1 and 3 :\ zero\ one\ infinitely many\ Equations 2 and 3:\ zero\ one\ infinitely many

following system has one solution: x=2,y=2, and z=3. 4x2y+5z=27 Equation 1 x+y=0 Equation 2 x3y+2z=10 Equation 3 (a) Solve the system provided by Equations 1 and 2. (If there is no solution, enter NO SOLUTION. If the system has an infinite number of solutions, express x,y, and z in terms of the parameter t. ) (x,y,z)=() (b) Solve the system provided by Equations 1 and 3. (If there is no solution, enter NO SOLUTION. If the system has an infinite number of solutions, express x,y, and z in terms of the parameter t. (x,y,z)=() (c) Solve the system provided by Equations 2 and 3. (If there is no solution, enter NO SOLUTION. If the system has an infinite number of solutions, express x,y, and z in terms of the parameter t.) (x,y,z)=() (d) How many solutions does each of these systems have? Equations 1 anct2: zero one infinitely many Equations 1 and 3: zero one infinitely many Equations 2 and 3 : zero one infinitely many