The following table provides a probability distribution for the random variable y.

y	p(y)
2	0.20
4	0.40
7	0.10
8	0.30

(a)Compute

E(y).

(b)Compute Var(y) and . (Round your answer for to two decimal places.)

Var(y)=

=

2. West Virginia has one of the highest divorce rates in the nation, with an annual rate of approximately 5 divorces per 1,000 people. The Marital Counseling Center, Inc. (MCC) thinks that the high divorce rate in the state may require them to hire additional staff. Working with a consultant, the management of MCC has developed the following probability distribution for x = the number of new clients for marriage counseling for the next year.

x	f(x)
10	0.05
20	0.10
30	0.10
40	0.20
50	0.35
60	0.20

a)Is this probability distribution valid? Explain.

This probability distribution

is is not valid because

1 f(x) 1 10 f(x) 60 f(x) 0 f(x) 0 for

x= 10, 20, 30, 40, 50, 60.

What is the probability MCC will obtain more than 30 new clients?

What is the probability MCC will obtain fewer than 20 new clients?

Compute the expected value and variance of x.

expected value of x

variance of x

Please explain step by step so I can understand.