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The form of the partial fraction decomposition of a rational function is given below. (9x + 20x +45) (x+5)(x+9) A = B = C
The form of the partial fraction decomposition of a rational function is given below. (9x + 20x +45) (x+5)(x+9) A = B = C = Now evaluate the indefinite integral. - (9x + 20x +45) (x+5)(x+9) dx = A Br+C = + 2+5 z+9
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