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The Fourier series coefficients X of the signal x(t) ==- 108(2t - 0.5n) is: 8 810 O 1. 10 - 8(f -0.5n) 02. 20
The Fourier series coefficients X of the signal x(t) ==- 108(2t - 0.5n) is: 8 810 O 1. 10 - 8(f -0.5n) 02. 20 - 8(f - 4n) O 3. 10 - 8f 0.25n) O 4. None of the answers O 5. 2.5 - 8(f - 4n)
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