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The free energy change for the following reaction at 25 C, when [H*] = 8.48x10-3 M and [Fe3+] = 1.12 M, is 161 kJ: 2.00H*(8.4810-
The free energy change for the following reaction at 25 C, when [H*] = 8.48x10-3 M and [Fe3+] = 1.12 M, is 161 kJ: 2.00H*(8.4810- M) + 2Fe2+ (aq)H(g) + 2Fe+(1.12 M) AG = 161 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction
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Organic Chemistry
Authors: Robert Thornton Morrison, Robert Neilson Boyd
6th Edition
8120307208, 978-8120307209
