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The function f(x) = - 0.1(x - 1)?(x - 3) QUESTION 5 Perform the following division (use synthetic or long division) x4+7x3 + x2 -44x
The function f(x) = - 0.1(x - 1)?(x - 3) QUESTION 5 Perform the following division (use synthetic or long division) x4+7x3 + x2 -44x +6 x+5 The quotient of this division will be of the form ax + bx + cx + d . State the values of a, b, c, and d below: a = b = c = d = State the remainder of this division: QUESTION 6 rchers know that the temperature gradients within a snowpack are highly respons Fill in the blanks for the following statement. Refer to the Factor and Remainder Theorems found in Unit 2 Chapter 5. embersure in degrees Celsius) just above the snow surface over a period of seven hours. Note: If you are entering a value, enter an integer. If you are entering a factor, then use brackets, such as (x-4). hatch the folowing features of the graph to their corresponding meanings. Meaning of x-intercepts A. Temperature, in degrees Celsius ring of y-inberce B. (3.6) G. Time, in hours If the polynomial function q(x) has the zero x = 5 this means is a factor of q(x) and q(5) = . Title of y-axis D. (3.6] - Title of Graph E. The maximum air temperature during data colection . Practical Domain F. 10.7] QUESTION 7 . v/Time interval in which the air temperature at the surface of the snowpack is G. The minimum air temperature during data collection H. At the start of data collection the surface temperature of the snowpack is -1.8 The polynomial function k(x) has the following zeros: J. Temperature changes at the surface of a snowpack over a seven hour period K. At hour 1, 3, and $ after the start of data colection the temperature at the surface of the snowpack reaches 0 degrees Celsius x =3+ iv5,3-iV5,V31, -V31, -2,1,iV2, - iV2 Classify these zeros as being rational, irrational, complex, or imaginary. QUESTION 4 The zeros x = 3 + iv5 are Given the following polynomial, The zeros x = + iv2 are p(x) =3x3 -6x2 + 11x -8 The zeros X = - 2, 1 are According to the rational zero theorem, the possible zeros for p(x) are + 1,2,4,8 The zeros X = + 31 are 1,3 It turns out x= 1 is a true zero of p(x). You can perform synthetic division to rewrite p(x) in the factored form gi p(x) = (x-1)(ax
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