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The function f(x) = 4t^3 - 57t^2 + 210t + 6 is the vertical location of an object where f is in ft and t
The function f(x) = 4t^3 - 57t^2 + 210t + 6 is the vertical location of an object where f is in ft and t is in sec.
- Solve for an expression for the object's velocity.
- Solve for an expression for the object's acceleration.
- Solve for an expression for the object's speed.
- Solve for its displacement during the beginning five secs.
- Solve for its average velocity during the beginning five secs.
- Solve for the instantaneous velocity where time is 2.
- Solve for the acceleration of the object where time is 2.
- For which values will the object change direction?
- Solve for the acceleration each time the object changes direction.
- Solve for the speed of the object when time is 3 secs.
- Solve for the total distance the object travels over the beginning ten secs.
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