The general form of the equation of a straight line can be expressed as Ax + By +C =0 with a condition that A and B cannot both be zero. This equation can also be expressed as: y==(4x+C). Given a straight line, 2x -y + 1 = 0, one can re-write the equation as y=2x+1 and then use it to find few points that are on the line. Here are some example values: B -1 0 1 2 y = 2x + 1 y = 2 * (-1) + 1 = -1 y = 2 x 0 + 1 = 1 y = 2 x 1 + 1 = 3 y= 2 2 + 1 = 5 Point (-1,-1) (0,1) (1,3) (2,5) Instruction: 1. Use Notepad to create new text file named EX03_1.java. Enter the following two lines (be sure to replace YourFullName with your full name): 96 Java Programming - Penniel P. Wu, PhD // FileName: EX03_1.java // Programmer: YourFullName 2. Create a Java program that will take inputs of A, B, and C (as integers) from users. Reject the inputs if both A and B are zeros; otherwise, find two points on the line and display them in the form of (x, y). 3. Make sure the output looks similar to the following.. [Note: Be sure to use input an output dialog boxes, otherwise, you might receive zero.] Input x Input x Input ? Enter A: ? Enter B: ? Enter C: 5 OK Cancel OK Cancel OK Cancel and Message Equation 3x+4y+5-0 Includes two points: (1.0,-1.25) (2.0, -20) OK