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The height (feet) of a ball launched in the air t seconds after it is launched is given by: f(t) = - 161- +218t +

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The height (feet) of a ball launched in the air t seconds after it is launched is given by: f(t) = - 161- +218t + 15. The velocity of the ball when at a height of 120 feet is |fu/sec. If necessary, round to two decimal places. If there is more than one correct answer, separate them with commas

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