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The height (feet) of a ball launched in the air t seconds after it is launched is given by: f(t) = - 1612+312t+ 14. Find

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The height (feet) of a ball launched in the air t seconds after it is launched is given by: f(t) = - 1612+312t+ 14. Find the height of the ball when it is falling at 120 fu/sec. . . . The height is feet. If necessary, round to two decimal places. If there is more than one correct answer, separate them with commas

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