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The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 21.5

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The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 21.5 m/s is h 2+21.5t-4.9t2 after t seconds. (a) Find the velocity (in m/s) after t seconds. v(t) = 1.9 Find the velocity (in m/s) after 2 seconds and after 4 seconds. v(2)=1.9 v(4)=-17.7 m/s m/s (b) What is the value (in m/s) of v(t) when the projectile reaches its maximum height? v(t) = 2.19 m/s When (in s) does the projectile reach its maximum height? (Round your answer to two decimal places.) S (c) What is the maximum height (in m)? (Round your answer to two decimal places.) 25.58 m (d) When (in s) does it hit the ground? (Round your answer to two decimal places.) S (e) With what velocity (in m/s) does it hit the ground? (Round your answer to two decimal places.) m/s

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