The height (in meters) of a projectile shot vertically upward from a point 4 m above...

 

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The height (in meters) of a projectile shot vertically upward from a point 4 m above ground level with an initial velocity of 22.5 m/s is h = 4 + 22.5t - 4.9t after t seconds. (a) Find the velocity (in m/s) after t seconds. v(t) = Find the velocity (in m/s) after 2 seconds and after 4 seconds. v(2) = 2.9 v(4) = -16.7 m/s m/s (b) What is the value (in m/s) of v(t) when the projectile reaches its maximum height? v(t) = m/s When (in s) does the projectile reach its maximum height? (Round your answer to two decimal places.) S (c) What is the maximum height (in m)? (Round your answer to two decimal places.) m (d) When (in s) does it hit the ground? (Round your answer to two decimal places.) S (e) With what velocity (in m/s) does it hit the ground? (Round your answer to two decimal places.) m/s The height (in meters) of a projectile shot vertically upward from a point 4 m above ground level with an initial velocity of 22.5 m/s is h = 4 + 22.5t - 4.9t after t seconds. (a) Find the velocity (in m/s) after t seconds. v(t) = Find the velocity (in m/s) after 2 seconds and after 4 seconds. v(2) = 2.9 v(4) = -16.7 m/s m/s (b) What is the value (in m/s) of v(t) when the projectile reaches its maximum height? v(t) = m/s When (in s) does the projectile reach its maximum height? (Round your answer to two decimal places.) S (c) What is the maximum height (in m)? (Round your answer to two decimal places.) m (d) When (in s) does it hit the ground? (Round your answer to two decimal places.) S (e) With what velocity (in m/s) does it hit the ground? (Round your answer to two decimal places.) m/s

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a To find the velocity vt after t seconds we differentiate the height function ht 4 225t 49t2 with r... View the full answer