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The height of a projectile shot vertically upwards from the Earth's surface with an initial velocity of 40 m/s is given by ()=404.92h(t)=40t4.9t2 after t

The height of a projectile shot vertically upwards from the Earth's surface with an initial velocity of 40 m/s is given by ()=404.92h(t)=40t4.9t2 after t seconds. At what time and with what velocity does the projectile hit the ground?

please answer using differentiation, thank you.

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