The Henry's law constant for O$2$ in water is $1\mathrm{.}32$x$10-3$ M$/$atm$.$ Determine the solubility $($in M$)$ of O$2$ at an atmospheric pressure of $1\mathrm{.}75$ atm. The mole fraction of oxygen in the atmosphere is $0\mathrm{.}21.$ Express your answer in scientific notation, using the format $($for example$)2\mathrm{.}5*10^-5$ for $2\mathrm{.}5$x$10-5.$