The image above shows the graph of polar function 5" = 2 Sin 5', with the right half shaded. The graph is a circle, with diameter 2. From prior experience with the geometry of circles, we know that the area of this half-circle region is (WQNZ = 7rf2. {This circle has radius r=1.} In the following three problems, we'll step away from geometry of circles. Instead, we'll explore the integration technique that can be used to arrive at the same result, area: rrf2. Consider the given function, r = 2 sin 0. The shaded region (shown above) lies in the O interval 0