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The inverse forms of the results in Problem 49 in Exercises 7.1 are s-a = (sa). +62 - eat cos bt and b (sa)

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The inverse forms of the results in Problem 49 in Exercises 7.1 are s-a = (sa). +62 - eat cos bt and b (sa) + = eat sin bt. +62 Use the Laplace transform and these inverses to solve the given initial-value problem. y' + y = e5t cos 4t, y(0) = 0 v(t) =

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