The Laplace transform of the solution of the IVP:

$f^{\text{'}\text{'}}(t)-f^{\text{'}}(t)-f(t)=1,f(0)=f^{\text{'}}(0)=0$ satisfies:

Select one:

$F(s)=\frac{1}{s(s^2+s-1)}$

$F(s)=\frac{1}{s(s^2+s+1)}$

$F(s)=\frac{1}{s(s^2-s-1)}$

$F(s)=\frac{1}{s^2(s^2-s-1)}$

$F(s)=\frac{1}{s(s^2-s+1)}$