The laser photolysis of 6,6,7,7-tetrafluoro-7-bromoheptene, in the presence of (TMS)3SiH (a radical chain carrier), at 25C has been observed to form the following three products: F F F F F -F F LF F F F F 8 9 10 At a (TMS)3SiH concentration of 0.1 M, 8 (11%), 9 (85%), and 10 (5%) were found. When this concentration was increased to 0.6 M, 8 (42%), 9 (55%), and 10 (3%) were found. (i) Using mechanistic diagrams detail the three reaction pathways for the formation of 8, 9, and 10. 8 marks (ii) Rank the three precursor radicals that directly lead to the formation of 8, 9, and 10 in order of increasing stability. Explain your reasoning. 2 marks Question A2 continues on the next page Section A continues on the next page Section A (continued) Question A2 (continued) (iii) Explain why 9 is the major product. 2 marks (iv) Why does the fraction of 8 increase as the concentration of (TMS):SiH is increased? 2 marks