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The Law of Cosines: For any triangle with side A across from angle A, side b across from side B, and side c across from
The Law of Cosines: For any triangle with side A across from angle A, side b across from side B, and side c across from angle C, c2 = a2+ 62 - 2ab cos C Similarly, a2 = 62 + c2 - 2bc cos A b2 = a2 + c2 - 2ac cos BFind all missing measurements for the triangle with b=22.7, c=14.2, and A=220. Using the Law of Cosines, a2 = (22.7)2+( [ Select ] V )2-2(22.7) ( [ Select ] v cos [ Select ] V [ Select ] V We can use the Law of Sines to find the two missing angles.Find the Missing [Select] v [Select] sin 22 sin B 22.7 sin 220 ' B = 7:: 0.78 m 10.9 sin1(0.78) \"2:: 513 14.2 sin 22 ' = f2: .4 3111 C 10.9 0 88 sin1(0.488) a: 292 e Missing Angles [ Select ] = sin B sin CThe problem with those two angles is [ Select ] v . Since [59ml] V is the longest side, it must be opposite the largest angle, which must mean B is an obtuse angle with a reference angle of 513. B = [Select] V 0 and c = 29.2
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