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The length of a rectangle is 5 cm more than its width and the area is 50cm2. Find the length, width and the perimeter. Let
The length of a rectangle is 5 cm more than its width and the area is 50cm2. Find the length, width and the perimeter.
Let the width be x. Then the length = x + 5.
x(x + 5) = 50
x2+ 5x = 50
-50 => x2+ 5x - 50 = 0
(x + 10)(x -5) =0
(x + 10) = 0 or (x -5) =0
x = -10 or x = 5 - x = -10 is impossible to be a width
Width = 5cm; so, the length = 10cm.
Perimeter = 30cm.
solve this question by any method of Quadratic equation mean
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