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The length of life of a new type of tap has a distribution with pdf f(x; ) = (x/ ^ 2) e ^(x/) x >

The length of life of a new type of tap has a distribution with pdf f(x; ) = (x/ ^ 2) e ^(x/) x > 0, > 0. Thirty taps were given a life test and the mean failure time was 1000 hours. Use the likelihood ratio test to determine whether the observed result justifies the manufacturer's claim that is 900 hours

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