Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

The liquid-phase elementary reaction 2A->B+C is carried out adiabatically in a 5dm^(3) PFR. The heat of reaction at 298K is -10,000ca(l)/(m)olA . The feed

The liquid-phase elementary reaction

2A->B+C

is carried out adiabatically in a

5dm^(3)

\ PFR. The heat of reaction at

298K

is

-10,000ca(l)/(m)olA

. The feed is equal molar in A and\ in inerts at

77\\\\deg C

, with

F_(A)=10mo(l)/(m)in

and

C_(AO)=4mo(l)/(d)m^(3)

. Write the polymath code\ with explanation for calculating the PFR volume required for

75%

conversion.\ Additional information:\

C_(pA)=18ca(l)/(m)ol,C_(pB)=C_(pC)=9ca(l)/(m)ol

, and

C_(p, inert )=15ca(l)/(m)ol

\

k=10^(-6)dm^(3)mol*min

at

360K

with

E=6,000ca(l)/(m)ol

\ The energy balance equation is given by,\

T=T_(i,o)-(\\\\Delta Hrxn(T)x_(A))/(\\\\sum_(i=1)^n \\\\theta _(i)C_(p,i))
image text in transcribed
The liquid-phase elementary reaction 2AB+C is carried out adiabatically in a 5dm3 PFR. The heat of reaction at 298K is 10,000cal/molA. The feed is equal molar in A and in inerts at 77C, with FA=10mol/min and CA0=4mol/dm3. Write the polymath code with explanation for calculating the PFR volume required for 75% conversion. [5] Additional information: CpA=18cal/mol,CpB=CpC=9cal/mol, and Cp, inert =15cal/mol k=106dm3molmin at 360K with E=6,000cal/mol The energy balance equation is given by, T=Ti,0i=1niCp,iHrxn(T)XA

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Students also viewed these Chemical Engineering questions