The manager at a dairy farm has five similar cans of $50$ litres capacity $-$ A$,$ B$,$ C$,$ D and E$-$ full of mixtures of milk and water. The ratio of milk and water in each can is different. It is known that the cost price of pure milk is Rs$.25$ and water is free of cost$.$ When he sells the entire contents of can E at Rs$.1,250,$ the manager earns a profit of $25\%.$ Can C contains $20$ litres more of milk than water. If the manager sells the mixture can B at the cost price of milk, he earns a profit of $100\%.$ The cost price of the mixture in can D is Rs$.800.$ The water content in can A is as much less than can B as it is more than can C$.1.$ If equal quantities of mixtures from can A and B are mixed in a new vessel, then what is the percentage of milk in the new mixture? a$)40\%$ b$)50\%$ c$)55\%$ d$)48\%2.$In what ratio should the mixtures from cans B and C be mixed to obtain a mixture that has a cost price of Rs$\mathrm{.}16\mathrm{.}50$ per liter? a$)2$:$3$ b$)1$:$4$ c$)1$:$2$ d$)4$:$33.$If the dairy manager sells the entire contents can D by marking it at the cost price of pure milk and allowing a discount of $23\%$ on the marked price, then what is the approximate gain or loss $\%$ for him in this transaction? a$)3\%$ gain $12\%$ loss c$)5\%$ loss d$)20\%$ gain $4.$If contents from cans A and E are mixed in the ratio $4$ :$3,$ then what is the ratio of milk and water in the new mixture? a$)24$: $11$ b$)29$:$6$ c$)22$: $13$ d$)26$:$95.$Mixtures from cans C and E are mixed in equal quantities. What should be the selling price per litre of the new mixture so as to earn a profit of $40\%?$ a$)$ Rs$\mathrm{.}35$ b$)$ Rs$\mathrm{.}27\mathrm{.}50$ c$)$ Rs$\mathrm{.}26\mathrm{.}25$ d$)$ Rs$\mathrm{.}28\mathrm{.}75$