The manager of a major manufacturer of golf equipment, UBall, believes that market share could be increased with the introduction of a cut-resistant, longer-lasting golf ball and asks the inhouse research group to investigate a new golf ball coating designed to resist cuts and provide a more durable ball. Though the tests with the coating have been promising, one of the researchers voiced concern about the effect of the new coating on driving distances. UBall would like the new cut-resistant ball to offer driving distances comparable to those of the current-model golf ball.

To compare the driving distances for the two balls, 40 randomly selected balls of the current model and 40 randomly selected balls of the new model were subjected to distance tests. The testing was performed with a mechanical hitting machine so that any difference between the mean distances for the two models could be attributed to a difference in the two models. The distances measured to the nearest meter were recorded.

Using this data, a researcher generated the followingRprintouts. On these printouts, the driving distances are labelledCurrentandNew, respectively.

Driving distance - Current model 0.00 0.01 0.02 0.03 0.04 0.05 Density 220 230 240 250 260 270 CurrentDriving distance - New model 0.06 0.04 Density L 0.02 0.00 220 230 240 250 260 270 NewCurrent New median 247 . 0000 242 . 0000 mean 247 . 1000 244 . 6250 SE . mean 1. 2663 1. 4272 CI . mean . 0.95 2 . 5614 2. 8867 var 64 . 1436 81 . 4712 std . dev 8 . 0090 9 . 0261 coef. var 0. 0324 0. 0369 skewness 0 . 2811 0. 2494 skew . 2SE 0. 3760 0. 3336 kurtosis -0. 9630 -0. 7419 kurt . 2SE -0. 6573 -0. 5063 normtest . W 0. 9655 0. 9602 normtest . p 0. 2567 0. 1702Paired t-test data: Current and New t = 1. 2415, df = 39, p-value = 0. 2218 alternative hypothesis: true difference in means is not equal to 0 95 percent confidence interval: -1. 557387 6. 507387 sample estimates : mean of the differences 2. 475 Two Sample t-test data: Current and New t = 1. 2972, df = 78, p-value = 0. 1984 alternative hypothesis: true difference in means is not equal to 0 95 percent confidence interval: -1. 323486 6. 273486 sample estimates : mean of x mean of y 247 . 100 244 . 625Welch Two Sample t-test data: Current and New t = 1. 2972, df = 76.911, p-value = 0. 1984 alternative hypothesis: true difference in means is not equal to 0 95 percent confidence interval: -1. 324334 6. 274334 sample estimates : mean of x mean of y 247 . 100 244 . 625 F test to compare two variances data: Current and New F = 0. 78732, num df = 39, denom df = 39, p-value = 0. 4587 alternative hypothesis: true ratio of variances is not equal to 1 95 percent confidence interval: 0 . 4164112 1. 4885944 sample estimates: ratio of variances 0. 7873166Exact Wilcoxon signed rank test data : Current and New V = 444, p-value = 0. 2911 alternative hypothesis: true mu is not equal to 0 Exact Wilcoxon rank sum test data : Current and New w = 924.5, p-value = 0.2321 alternative hypothesis: true mu is not equal to 0