The mean amount of life insurance per household is $129,000. This distribution is positively skewed. The standard deviation of the population is $36,000. Use Appendix EH for the zvalues. a. A random sample of 60 households revealed a mean of $133,000. What is the standard error of the mean? (Round the final answer to 2 decimal places.) Standard error ofthe mean b. Suppose that you selected 133,000 samples of households. What is the expected shape of the distribution of the sample mean? Shape (Click to select) v c. What is the likelihood of selecting a sample with a mean of at least $133,000? (Round the final answer to 4 decimal places.) Probability d. What is the likelihood ofselecting a sample with a mean of more than $121,000? (Round the final answer to 4 decimal places.) Probability e. Find the likelihood of selecting a sample with a mean of more than $121,000 but less than $133,000. (Round the final answer to 4 decimal places.) Probability The Crossett Trucking Company claims that the mean mass of its delivery trucks when they are fully loaded is 2800 kg and the standard deviation is 70 kg. Assume that the population follows the normal distribution. Forty trucks are randomly selected and their masses measured. Within what limits will 95% of the sample means occur? (Round the final answers to the nearest whole number.) Sample means to The average grade in a statistics course has been 77 with a standard deviation of 115. If a random sample of 57 is selected from this population, what is the probability that the average grade is more than 81? Use Agpendix Bil for the zvalues. (Round your z-value to 2 decimal places and the final answer to 4 decimal places.) Probability A population consists of the following five values: 4, 4, 2, 32, 33. a. Not available in Connect. b. By listing all samples of size 3, compute the mean of the distribution of the sample mean and the population mean. Compare the two values. (Round the final answer to the nearest whole number.) Sample means Population mean Both means are (Click to select) v c. Compare the dispersion in the population with that ofthe sample means. Hint Use the range as measure of dispersion. The dispersion of the population is (Click to select) v than that of the sample means. A manufacturing process produces 5% defective items. What is the probability that in a sample of 50 items: a. 9% or more will be defective? (Round the zvalue to 2 decimal places and the final answer to 4 decimal places.) Probability b. less than 3% will be defective? (Round the z-value to 2 decimal places and the final answer to 4 decimal places.) Probability c. more than 9% or less than 3% will be defective? (Round the z-value to 2 decimal places and the final answer to 4 decimal places.) Probability
