The method findLargest should return the largest of any number of double values. For example, the call findLargest (3.4, -2.6, 2.9) should return 3.4 and the call findLargest (9.2, 17.6, 3.4, -2.6, 2.9) should return 17.6. Partial code to do this is given below:

double findLargest (double... values)

{

 double max = values[0];

 // New code goes here 

 return max;

}

What code will complete this method?

A)

for (double val: values)

{

 if (val > max)

 {

 max = val;

 }

}

B)

for (int i = 1; i < values.length; i++)

{

 if (i > max)

 {

 max = i;

 }

}

C)

for (double val:values)

{

 if (values[val] > max)

 {

 max = values[val];

 }

}

D)

for (int i = 1; i < values.length; i++)

{

 if (values[i] > max)

 {

 max = i;

 }

}

Please give an explanation!