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The motion of a stone thrown into a pond is described by r(t) = ((1.5-0.3e-13.6t) + (0.094e-13.6t - 0.094 -0.72t) ) m where t

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The motion of a stone thrown into a pond is described by r(t) = ((1.5-0.3e-13.6t) + (0.094e-13.6t - 0.094 -0.72t) ) m where t is time expressed in seconds, and t= 0.2 s is the time when the stone first hits the water. Determine the stone's velocity and acceleration. In addition, find the initial angle of impact of the stone with the water, i.e., the angle formed by the stone's trajectory and the horizontal direction at t= 0.2. (Include a minus sign if necessary.) The stone's velocity is (( The stone's acceleration is (( | The initial angle of impact is e-13.60) i + (| e-13.60) i + ]) ) m/s. (Round the final answers to two decimal places.) 13.60j ) m/s. (Round the final answers to two decimal places.) e-13.60t+ e . (Round the final answer to four decimal places.)

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