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The NMR spectrum of bromocyclohexane indicates a low field signal (1H) at 4.16. To room temperature, this signal is a singlet, but at -75 C
The NMR spectrum of bromocyclohexane indicates a low field signal (1H) at 4.16. To room temperature, this signal is a singlet, but at -75 C it separates into two peaks of unequal area (but totaling one proton): 3.97 and 4.64, in ratio 4.6: 1.0. How do you explain the doubling in two peaks? According to the generalization of the previous problem, what conformation of the molecule predominates (at -75 C)? What percentage of the molecules does it correspond to?
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