The normal freezing point of benzene $(C_6{H}_6)$ is $5\mathrm{.}5C.$ If $24\mathrm{.}98$ grams of the nonvolatile nonelectrolyte juglone $(C_{10}{H}_6{O}_3),$ are dissolved in $292\mathrm{.}1$ grams of benzene, what is the freezing point of the resulting solution? $K_{fp}$ for benzene is $5\mathrm{.}12\frac{C}{m}.$

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