The normal freezing point of water, H$2$O is $0\mathrm{.}00\backslash$deg C and its Kfp value is $1\mathrm{.}86\backslash$deg C$/$m$.$

Assuming complete dissociation of the electrolyte, if $11\mathrm{.}22$ grams of ammonium nitrate $($NH$4$NO$3,80\mathrm{.}06$ g$/$mol$)$ are dissolved in $168\mathrm{.}0$ grams of water what is the freezing point of the solution?

$\backslash$deg C