The normal freezing point of water, $H_{2}O$ is $0\mathrm{.}00C$ and its $K_{fp}$ value is $1\mathrm{.}86\frac{C}{m}.$

Assuming complete dissociation of the electrolyte, if $10\mathrm{.}53$ grams of ammonium iodide $(N{H}_{4}l,145\mathrm{.}0\frac{g}{m}ol)$ are dissolved in $189\mathrm{.}1$ grams of water what is the freezing point of the

solution?