The null and alternate hypotheses are:

H₀ : _d 0 H₁ : _d > 0

The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of 4 days last month.

Day

1 2 3 4

Day shift 11 12 13 19

Afternoon shift 9 10 14 15

At the 0.03 significance level, can we conclude there are more defects produced on the day shift? Hint:For the calculations, assume the day shiftas the first sample.

Required: a. What is the p-value?NOTE: P-value calculators are available through online search. (Round your answer to 4 decimal places.)

P-VALUE_____________________________.

b. What is your decision regarding the null hypothesis?

• Do not reject H₀
• Reject H₀

c. What is the conclusion indicated by the analysis?

THERE ARE MORE DEFECTIVE PARTS PRODUCED ON_____________. PLEASE CHOOSE ONE OF THE FOLLOWING.

THE DAY SHIFT

THE AFTERNOON SHIFT.