The originators of the Six Sigma quality idea reasoned as follows. Short$-$term process variation is desc term, the process mean $$ will also vary. Studies show that, in most manufacturing processes, $+-1\mathrm{.}5$ is : changes in $.$ The Six Sigma standard is intended to allow the mean $$ to be as much as $1\mathrm{.}5$ away from specifications and still meet high standards for percent of output lying outside the specifications.

Sketch the specification limits and a Normal distribution for process output when $C_p=2$ and the mean center of the specifications.

What is $C_{pk}$ in this case?

Give your answer for $C_{pk}$ to one decimal place.

$C_{pk}=$

Incorrect

Is Six Sigma quality as strong a requirement as $C_{pk}2?$

The Six Sigma quality as strong a requirement as $C_{pk}2.$

Feedback

You have not provided the co value of $C_{pk}.$ The performan capability index $C_{pk}$ is

$|)/(3$

To find $,$ use the phrase $"$t

$1\mathrm{.}5$ away from the center."

LSL and USL, use the pote capability equation index $C_p=\frac{\text{U}\text{S}\text{L}-LSL}{{}_{}}=2.$

For the Six Sigma quality center is at $0.$