The output of the command: t=linspace(1, 10, 100); y=exp(t/5).*cos(t).*sqrt((t)-1); plot(t,y) is the graph of the function: f(t) = evt - 1 cost f(t) = e(Vt 1) cost = O the above O the above f(t) = et (Vt 1)cost Error. . The right commands to solve the following system of differential equations are: { x' = 2x - 6y, x(0) = 1 ly' = x + 3y, y(0) = -2 syms x(t) y(t) odel=diff(x.t)=2*x-6*y. ode2=diff(y.t)=x+3*y, odes=(odel;ode2] condl=x0=1; cond2=y(0)==-2; conds=[condl;cond2]; [xSol(t).ySolt)] = dsolve(odes,conds) odel=diff(x,t)=x+2*y: ode2=diff(y,t)=3*x+2*y: odes=(odel:ode2]: condl=x(0)=1: cond2=y(0)== -2: conds=[condl:cond2]; [xSol(t).ySol(t)]= dsolve(odes.conds) the above the above syHus X4) V) dsolve diffx.1=2*x - 6*y, diffty.1)=x+3*y, x0=1,0-2) syms x(t) y(t) odel=diff(x,1)=x+2*y; ode2-diff(y,t)=3*x+2*y, odes Codel:ode2] conds=[condl:cond2]; [xSol(t),ySol(0] = dsolve(odes.conds) the above the above How to create a mesh for the following vectors: X= vector from -20 till 20 with increment of 8 Y=vector from - 10 till 10 with increment of 4 Z= (sin X)*(sinY) X=-20:8:20: Y=-10:4:10: Z=sin(X). *sin(Y); plot3(X,Y.Z); meshgrid X=-20:8:20: Y=-10:4:10; [X,Y)=meshgrid (rangeX, rangeY); Z=sin(X).* sin(Y); mesh(X,Y,Z) the above the above rangeX=-20:8:20: range Y--10:4:10; [X,Y] meshgrid (rangeX, rangeY); Z-sin(X).* sin(Y); mesh(X,Y,Z) None of the other options O the above the above If we plot the pie chart for the values given in the vector X = [x 2x x/2), where x is a real number = 0. we obtain : 124 $ 150 X None of the other options 180 X/2 240 300 270 the above the above 14% 17% 29% 50% 33% 57% O the above the above