The phosphorylation of glucose to glucose 6-phosphate is the initial step in the catabolism of glucose. The direct phosphorylation of glucose by P; is described by the equation Glucose + Pi glucose 6-phosphate + H20 AG' = 13.8 kJ/mol The phosphorylation of glucose in the cell is coupled to the hydrolysis of ATP. Part of the energy from ATP hydrolysis is used to phosphorylate glucose. Glucose + Pi - glucose 6-phosphate + H20 AG = +13.8 kJ/mol ATP + H20 ADP + Pi AG' = -30.5 kJ mol Sum: Glucose + ATP glucose 6-phosphate + ADP Calculate K'eq at 37.0 C for the overall reaction. Kq= The maximum solubility of glucose is less than 1 M. The normal physiological concentration of glucose 6-phosphate (G6P) is 250 M. If the concentration of ATP is 3.38 mM and the concentration of ADP is 1.32 mM, what concentration of glucose is needed to achieve a 250 M intracellular concentration of G6P? -16.7 [Glucose) = M Determine whether the coupling of ATP hydrolysis to the phosphorylation of glucose provides a feasible route, at least in principle, for the phosphorylation of glucose in the cell. Is this coupling process feasible for glucose phosphorylation in the cell? O No. ATP hydrolysis has a negative free-energy change, so the ATP concentration should be higher. Yes. The concentration of ADP is sufficient to provide a substrate for more ATP synthesis. No. The phosphorylation of glucose is not spontaneous because it has a positive AG'. Yes. The concentrations of glucose and glucose 6-phosphate are within normal bounds