The physics of electric field and force and point charges. A +4.0 C charge, +q,, is 1.0 m to the left of a 1.0 C charge, +q2. a. What is the magnitude and direction of the force exerted at the location of the +92 charge? b. The charge +92 is now removed. The +q, charge produces an electric field at the location of point P. The magnitude of this electric field is 3.6 x 1010 N/C. Another charge +93 to the right of point P produces an electric field of magnitude 1.6 x 1010 N/C at point P. What is the total electric field strength at point P and what force would a +5.0 C charge experience at this point? c. The charge q, is now removed. It is replaced by a charge -q4. This charge is directly south of the point P and it produces an electric field of magnitude 2.6 x 1010 N/C. Draw a diagram representing the two electric fields. Then determine the magnitude and direction of the total electric field. Method of Evaluation The maximum grade for this solution is 5 points. The mark will be determined as follows. . 0.5 mark for determining the magnitude of the force for part a . 0.5 mark for determining the direction of the force for part a . 0.5 mark for determining the electric field for part b . 0.5 mark for determining the electric force for part b 1 mark for drawing the electric field vectors in the correct direction for part c 1 mark for determining the correct magnitude of the electric field for part c . 1 mark for determining the correct direction of the electric field for part c